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5k^2-33k-14=0
a = 5; b = -33; c = -14;
Δ = b2-4ac
Δ = -332-4·5·(-14)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-37}{2*5}=\frac{-4}{10} =-2/5 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+37}{2*5}=\frac{70}{10} =7 $
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